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When tasked with finding the next number for a list of values, it helps to work with what you know (that is, to work with familiar patterns), to be flexible (that is, to use various tools and tweaks), and to be willing to fail a few times (that is, to accept that you may need to take more than just one guess).
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Also, keep in mind that *any* formula or rule that you can logically justify is a valid answer. You don't (or at least shouldn't) have to get the same answer as everybody else, nor need your answer match the back of the book.
When trying to predict the next number in a sequence, try these suggestions:
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Most of all, be willing to accept that, many times, you won't see all the patterns right away. Any given list of numbers can have many, many "next" numbers that are correct — according to the many, many rules that can fit a given list. It's perfectly okay if you take a little while to find *your* answer.
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What follows are some worked examples, where you can see the thinking process at work.
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First, I'll see if anything happens to pop out at me.
To multiply from 3 to 4, I'd have to multiply by , but does not equal 6, so "multiply each term by " must not be the rule.
To add from 3 to 4, I'd have to add 1, but 4 + 1 is not 6; 6 is equal to 4 + 2. Wait....
If I assume that the operation here is addition, is there any pattern in what is added, when going from one term to the next? I'll check:
3 + 1 = 4
4 + 2 = 6
6 + 3 = 9
Hmm... What if the rule is "add the next whole number to the last term"? Then I'd have:
9 + 4 = 13
Does this fit? Do I get 18 for the next value?
13 + 5 = 18
Yup; it worked! So it would appear that my rule (one of many possible rules) is "add the next whole number to the previous term", and:
The missing number is 13.
The rule I came up with for the above list of numbers is kind of recursive. But I could have gone straight to the differences:
Since the second differences are the same, then the formula is a quadratic. Plugging in the first three data points, I get:
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a + b + c = 3
4a + 2b + c = 4
9a + 3b + c = 6
Solving this system of equations, I get:
an = 0.5n2 − 0.5n + 3
Plugging in n = 5 for the missing fifth term, I get:
a5 = 0.5(25) − 0.5(5) + 3 = 12.5 − 2.5 + 3 = 10 + 3 = 13
So my previous answer was right, or has at least been confirmed (by a second mathematical rule) as being logical.
(If the quadratic model had spit out a different answer, but still matched the original list's values, then I would have found a *second* perfectly valid solution. As long as you can logically justify your answer, it's okay if it doesn't match the back of the book or your classmates. If you've come up with something different, be proud! You've been clever!)
To add from 4 to 12, I'd have to use 8. To add from 12 to 20, I'd also have to use 8. Let's check to see if "add 8" is the rule:
4 + 8 = 12
12 + 8 = 20
20 + 8 = 28
28 + 8 = 36
Huh. It appears that the rule is "add 8". So what is the rule for the n-th term? Let's look at the terms:
n = 1: 4
n = 2: 4 + 8
n = 3: 4 + 8 + 8 = 4 + 2×8
n = 4: 4 + 8 + 8 + 8 = 4 + 3×8
n = 5: 4 + 8 + 8 + 8 + 8 = 4 + 4×8
It looks like the number of 8s at each stage is one less than the value of the index for that term (that is, of the value of n at that step). So I can state the pattern as:
n = 1: 4 + 0 = 4 + (1−1)×8
n = 2: 4 + 8 = 4 + (2−1)×8
n = 3: 4 + 8 + 8 = 4 + (3−1)×8
n = 4: 4 + 8 + 8 + 8 = 4 + (4−1)×8
n = 5: 4 + 8 + 8 + 8 + 8 = 4 + (5−1)×8
Following this pattern, the rule for the n-th term will be:
an = 4 + (n − 1)8
Take notice of how I did my solving. I tried various things, with some simple and familiar number lists. I didn't give up when my first one or two guesses were wrong. I was fine with using more than one method for solving a next-number problem.
Note also how I used the list's values to give me the information I needed for finding the formula. To help in this, I did not simplify the expressions. Writing out the logic of my work in terms of the index n, I was able more quickly to find the patterns.
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