As you have probably noticed by now, simplifying rational expressions involves a lot of factoring. If you're feeling at all rusty on this topic, review now: simple factoring, factoring quadratics, and special factoring formulas.
Also, once you're done factoring and simplifying, there is a way to use a graphing calculator to confirm whether your simplification is correct.
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Take the original expression, set it equal to y, and graph it. Then do the same with the simplified form. If the graphs match (other than any division-by-zero vertical asymptotes that simplification may have erased), then your answer is probably correct.
Faced with a polynomial fraction like this, many students will try to do something like the following:
Is this legitimate? Can the student really do this? (Think "bleeding, oozing...") You can NOT cancel term-by-term! You can ONLY cancel factors!
So the first thing I have to do — if I'm to have any chance of doing this simplification correctly — is factor the numerator and the denominator:
Since the numerator and denominator share a common factor, I can reduce the expression as:
Can I reduce any further? For instance, can I cancel off the x's? (whimpering, bleeding...) Can I cancel a 2 out of the 4 and the 6? (oozing, flopping...) No! This is as simplified as it's going to get, because there are no remaining common factors. Then the answer is:
Depending on your text or your instructor, you might not need that "for x not equal to part". However, since I cancelled off a 2x + 5 factor, this removed a division-by-zero problem from the original rational expression: namely, 2x + 5 = 0 for
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The factors in the numerator and denominator are almost the same, but not quite, so they can't be cancelled — yet. If the fraction had been:
...(that is, if the signs between the terms had been plusses instead of minuses), I could have rearranged the terms as:
...and cancelled to get 1, since order doesn't matter in addition. But order most definitely does matter in subtraction, so I can't just flip the subtraction to get matching factors. However, take a look at this:
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5 – 3 = 2
3 – 5 = –2
Do you see what happened? When I reversed the subtraction in the second line, I got the same number but the opposite sign. Then I can flip a subtraction, as long as I remember to change the sign; I'll flip the subtraction and kick out a "minus" sign.
So it turns out that I can reverse one of the subtractions in the original rational expression above, as long as I remember to switch the sign out front:
Now I can cancel:
Where did the 1s come from? Remember: If "nothing" is left, then a 1 is left. So, putting it all together:
(Depending on the text you're using, you may or may not need the "as long as x does not equal 2" part.)
You should keep this "flip a subtraction and kick a 'minus' sign out front" trick in mind. Depending on the text you're using, you may see a lot of this. And even if it doesn't come up much in the homework set, you should expect one of these on the next test.
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I can't cancel the x's; I can't cancel the 3 into the 12. I cannot reach inside (the parentheses that are understood to be around) the numerator and denominator, rip some pieces out, and try to cancel. (...big brown eyes...)
No; to simplify this, I first need to factor. Only once I have factors can I see if I there are any common factors that can be cancelled off.
Then my answer, accounting for the division-by-zero issue that I removed, is:
(You might not need the "for all x not equal to –3" part.)
To simplify this, I need to factor. Also, I can see that I will need to flip the subtraction in the denominator; I'll need to remember to change the sign when I do that flip.
Then my hand-in answer is:
(You might not need the "for all x not equal to 6" part.)
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